
Question #87b82 - Socratic
See a solution process below: First, we need to determine how much was left before the man spent 20%. We can rewrite this part of the problem as: 10200 is 80% of what? We are using 80% because …
Scale and Indirect Measurement Applications - Socratic
How tall is the dog if a man 6 feet tall is standing next to a dog and the man’s shadow is 9 feet and the dog’s shadow is 6 feet? How wide is the actual house if a model house is 12 inches wide and it was …
Question #07160 - Socratic
There is no concrete answer to this because it depends on your outlook on it. Below is a comparison of the two generals. After reading it, you can ultimately decide who you think was the better general. …
Question #b0092 - Socratic
1 Answer Narad T. Sep 7, 2017 The speed of the man is #=sqrt2/ (2-sqrt2)ms^-1# and the speed of the boy is #= (2sqrt2)/ (2-sqrt2)ms^-1#
Site Map - Isotope Notation Questions and Videos | Socratic
Questions What is the isotope notation for lithium? What is the isotope notation for carbon-14? What is the isotope notation for cobalt? In an isotope, which part of the atom changes? What are some …
Question #8b670 - Socratic
The reaction produces 20 g of "NO". > We are given the amounts of two reactants, so this is a limiting reactant problem. We know that we will need a balanced equation with masses, moles, and molar …
Questions asked by Divya Bezawada - Socratic
A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor of ? Four holes of radius R are cut …
Question #61851 + Example - Socratic
Nov 11, 2016 · I made some changes to the English. The changes are shown in capital letters. You can compare it to your original. I have not added or changed any of your ideas. Can you help me correct …
Question #5fb0a - Socratic
May 29, 2017 · The maximum speed at the bottom of the drop is 26.4m/s 3-The speed at the bottom of the drop is independent of the mass of the car. To find the speed of the car we will need to find how …
Question #8e21a - Socratic
Constant speed of Car A = 100km/h = 100 × 1000 3600 = 27.¯7ms−1 Let us consider Car B first. It enters the acceleration lane at a speed = 25km/hr = 6.9¯4ms−1. It accelerates uniformly and enters …